Divisional Alignment, Competitive Balance Style
So let's say that Florida State and Clemson join the Big 12. The conference would then need to determine divisions. Remember how the Big 10 did it? They took historical records of each program to determine competitive balance.
The Big 12 can do the same.
Listed below are the winning percentages and overall records of each program since the 1996 season (the inception of the Big 12). Schools not in the Big 12 for this time period are in italics.
Texas: 75.1% (154-51)
Oklahoma: 72.2% (151-58)
TCU: 71.4% (140-56)
Florida State: 71.0% (137-56)*
West Virginia: 66.7% (132-66)
Kansas State: 65.0% (130-70)
Texas Tech: 62.3% (124-75)
Clemson: 59.0% (118-82)
Oklahoma State: 58.2% (113-81)
Kansas: 42.6% (80-108)
Iowa State: 39.6% (76-116)
Baylor: 31.9% (59-126)
*A total of 12 wins in 2006 and 2007 were vacated.
The goal is to get both division's average winning percentage as close to the overall conference's as possible. I'm going to just ignore TCU's (it skews very high), but I'll factor in the other new schools'. The average of those 11 percentages is 58.5%.
The first thing to consider with divisions is likely that two Texas schools would be in each, as schools would want this for recruiting purposes. Seeing that one is first in wins and one is last, while the other two are middle of the road (considering TCU's inflation), it's a fair bet that UT/BU and TCU/TTU would be paired. We'll call UT and BU "Division A" and TCU/TTU "Division B" for now.
As Oklahoma has the next highest winning percentage and is also the next biggest brand, it's very unlikely that they would be with UT in Division A. I know those schools have said otherwise in the past, but it just doesn't make sense that way. Oklahoma is in Division B. This would also necessitate a protected crossover rivalry game between the divisions. Because OU and UT would be protected rivals, the Bedlam Game would only be saved by placing Oklahoma State in Division B as well.
Let's see where we are now:
Division A:
Baylor - 31.9%
Texas - 75.1%
Division B:
Oklahoma - 72.2%
Oklahoma State - 58.2%
TCU - 71.4%
Texas Tech - 62.3%
Florida State: 71.0% (137-56)*
West Virginia: 66.7% (132-66)
Kansas State: 65.0% (130-70)
Clemson: 59.0% (118-82)
Kansas: 42.6% (80-108)
Iowa State: 39.6% (76-116)
It doesn't make much logical sense to put the two lowest winning percentages in the same division, especially with the way that Division B is trending (some pretty high numbers there). Iowa State should belong in that division. Those four schools (excluding TCU) now have an average percentage of 58.1%, extremely close to the average. To keep it right on par, Clemson, who's right on the average, can round out Division B. That leaves four schools for Division A.
So, let's see where we ended up. Remember our goal is that 58.5% average:
Division A:
Baylor - 31.9%
Florida State - 71.0%
Kansas - 42.6%
Kansas State - 65.0%
Texas - 75.1%
West Virginia - 66.7%
Division A average winning percentage: 58.7%
Division B:
Clemson - 59.0%
Iowa State - 39.6%
Oklahoma - 72.2%
Oklahoma State - 58.2%
TCU
Texas Tech - 62.3%
Division B average winning percentage (excluding TCU): 58.3%
Protected rivalries would include Texas-Oklahoma and Baylor-TCU (among others, obviously). Each division ends up with two Texas schools, as well as exactly 4 "old" school and 2 "new" ones.
Yeah, I think that'd do it.