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TitanClone

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A ball thrown from 2 meters above the ground with a velocity of 6.8m/s at an angle of 60 degrees above the horizontal lands in a basket 2.3 meters away.

a) What is the height of the basket?
b)With what velocity (magnitude and angle) does the ball land in the basket? Neglect air resistance.

I just need help getting started, not looking for an answer. I think I'm just over thinking it because the 60 degrees is thrown in there.

Thanks in advance!
 
TitanClone said:
A ball thrown from 2 meters above the ground with a velocity of 6.8m/s at an angle of 60 degrees above the horizontal lands in a basket 2.3 meters away.

a) What is the height of the basket?
b)With what velocity (magnitude and angle) does the ball land in the basket? Neglect air resistance.

I just need help getting started, not looking for an answer. I think I'm just over thinking it because the 60 degrees is thrown in there.

Thanks in advance!
Click to expand...

Separate your initial velocity into horizontal and vertical components (cosine and sine, respectively), and then you have constant-velocity in the horizontal direction and constant acceleration (gravity, acting downward) in the vertical direction.

EDIT: from this you can find your ending velocities and use the tangent function to find the angle.
 
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iahawkhunter said:
Separate your initial velocity into horizontal and vertical components (cosine and sine, respectively), and then you have constant-velocity in the horizontal direction and constant acceleration (gravity, acting downward) in the vertical direction.

EDIT: from this you can find your ending velocities and use the tangent function to find the angle.
Click to expand...
Thanks!

Took me 2 minutes after staring at it for like 20.
 
CtownCyclone said:
Will the airplane take off? Or will it not? Are the bearings in the wheel frictionless? Is it an ideal plane?

That thread was priceless...I only wish I was around when it was written!
Click to expand...
Time to bring it back to rethink the solution.
 
CtownCyclone said:
Will the airplane take off? Or will it not? Are the bearings in the wheel frictionless? Is it an ideal plane?

That thread was priceless...I only wish I was around when it was written!
Click to expand...
Did anyone ask if the airplane was a Harrier or an Osprey?
 
I'm sure this problem is easy; I just can't find the correct formula to use. Anyone know it?

In November 2007, astronaut Pam Melroy, history’s second woman space
shuttle commander, flew the space shuttle Discovery to the International
Space Station to continue construction. To undock from the space station,
Commander Melroy released hooks holding the two spacecraft together and
the 76,700 kg shuttle pushed away from the space station with the aid of 4 large
springs. a) If the 232,700 kg space station moved back at a speed of 0.50 m/s,
how fast and in what direction did the space shuttle move
 
JUKEBOX said:
I'm sure this problem is easy; I just can't find the correct formula to use. Anyone know it?

In November 2007, astronaut Pam Melroy, history’s second woman space
shuttle commander, flew the space shuttle Discovery to the International
Space Station to continue construction. To undock from the space station,
Commander Melroy released hooks holding the two spacecraft together and
the 76,700 kg shuttle pushed away from the space station with the aid of 4 large
springs. a) If the 232,700 kg space station moved back at a speed of 0.50 m/s,
how fast and in what direction did the space shuttle move
Click to expand...

Momentum must be conserved, so the space station's momentum in one direction must be countered by the shuttle's momentum in the other (akin to equal and opposite forces). Since momentum is mass times velocity:

(232700)*(0.5) + (76700)*(v) = 0

The two terms sum to 0 because there is no initial relative velocity between the shuttle and the station. This will also give the shuttle velocity, v, as a negative number which will reflect the fact that the shuttle is moving in the opposite direction of the station.
 
iahawkhunter said:
Momentum must be conserved, so the space station's momentum in one direction must be countered by the shuttle's momentum in the other (akin to equal and opposite forces). Since momentum is mass times velocity:

(232700)*(0.5) + (76700)*(v) = 0

The two terms sum to 0 because there is no initial relative velocity between the shuttle and the station. This will also give the shuttle velocity, v, as a negative number which will reflect the fact that the shuttle is moving in the opposite direction of the station.
Click to expand...

This is what I thought, but they have a different answer on this website.
http://www.chsdarkmatter.com/hps10.pdf


I get 1.517 m/s, but they have 2.52 m/s.
 
I freaking hated 221. Thank God for graphing calculators with memory to store formulas (yeah, I cheated on some tests).
 
JUKEBOX said:
This is what I thought, but they have a different answer on this website.
http://www.chsdarkmatter.com/hps10.pdf


I get 1.517 m/s, but they have 2.52 m/s.
Click to expand...

Crap. After some internet searching here's what I've found:

Astronaur Pam Melroy flew the space shuttle Discovery to the International Space Station to complete? - Yahoo! Answers (same approach as I said above, but with different numbers)

Note that the linked problem asks for the relative velocity between the shuttle and station. If we do that here, you get 2.02 m/s (0.5 + 1.52), which makes up half the difference between your answer and the provided answer. I'm not sure where the remaining 0.5 m/s is coming from, and since the question just asks for the shuttle velocity I feel like the relative velocity between them is irrelevant.
 
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i think the answer comes out to going 75/75 on free throws...or maybe im getting it confused with something else
 
iahawkhunter said:
Crap. After some internet searching here's what I've found:

Astronaur Pam Melroy flew the space shuttle Discovery to the International Space Station to complete? - Yahoo! Answers (same approach as I said above, but with different numbers)

Note that the linked problem asks for the relative velocity between the shuttle and station. If we do that here, you get 2.02 m/s (0.5 + 1.52), which makes up half the difference between your answer and the provided answer. I'm not sure where the remaining 0.5 m/s is coming from, and since the question just asks for the shuttle velocity I feel like the relative velocity between them is irrelevant.
Click to expand...

I think I might just go with 1.52 and bite the bullet if it's wrong.
 
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