Friday OT #3- Logic Test

Depends. You haven't told us if the cards are unique...(no number or letter is repeated). If they are unique, you would have to turn over all four to be certain.

It doesn't matter if they're unique or not. It's based only on the cards that are given, not any remaining in the deck.
 
Depends. You haven't told us if the cards are unique...(no number or letter is repeated). If they are unique, you would have to turn over all four to be certain.

But that information is irrelevant, the only criteria is that a vowel must have an even number on the opposite side.
 
Some of you might have seen this one before as it's been around for 50+ years. It's a simple test to see how logical you are.

Here's how it works:
You have a set of cards in front of you. Each card is labeled with a number on one side and a letter on the other side. You are then given the rule that if a card has a vowel on one side, then it must have an even number on the other side. Four cards are then placed in front of you.

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Which card or cards do you have to turn over to determine whether or not the rule has been followed?

(Just post your answer, wait to post your reasoning until after we get a few responses)

It doesn't matter if they're unique or not. It's based only on the cards that are given, not any remaining in the deck.

Meh. I was over-thinking.

E & 9, then. If the E has an even number on the back or the 9 has a vowel on the back, the rule is disproved. Minimum, one card MUST turned...but if the E or 9 followed the rule, you would have to turn the other to be sure. If the first card breaks the rule, the second doesn't matter...the rule is already broken.

D & 4 would be immaterial.
 
Meh. I was over-thinking.

E & 9, then. If the E has an even number on the back or the 9 has a vowel on the back, the rule is disproved. Minimum, one card MUST turned...but if the E or 9 followed the rule, you would have to turn the other to be sure. If the first card breaks the rule, the second doesn't matter...the rule is already broken.

D & 4 would be immaterial.

Easily done, I think that's the intended result.